Calculation of the Formula: $1^3 + 2^3 + 3^3 + 4^3 + \dots + n^3$

The following Python code demonstrates how to calculate the sum of cubes of the first $n$ numbers, following the formula:

Requirement:

• Input: $n = 5$

• Output: 225

• Formula: $1^3 + 2^3 + 3^3 + 4^3 + 5^3 = 225$

• Input: $n = 7$

• Output: 784

• Formula: $1^3 + 2^3 + 3^3 + 4^3 + 5^3 + 6^3 + 7^3 = 784$

Example

# Function to calculate the sum of cubes
def sumOfSeries(n):
    total_sum = 0
    for i in range(1, n + 1):
        total_sum += i * i * i  # Cube of the current number
    return total_sum

# Call the function
n = 5
print(sumOfSeries(n))

Output

225

In this code, the function sumOfSeries(n) iterates from 1 to $n$, calculates the cube of each number, and accumulates the sum. For $n = 5$, the result is 225. Similarly, for $n = 7$, it will return 784.